Szia, a pop3 proxyban ez elég egyszerű, mert amúgy is parsolja a usernevet: class UserPolicyPop3Proxy(Pop3Proxy): def config(self): Pop3Proxy.config(self) self.banned_users = ("alma", "korte") self.request["PASS"] = (POP3_REQ_POLICY, self.checkUser) def checkUser(self, command): if self.username in self.banned_users: proxyLog(self, "pop3.policy", 3, "User administratively prohibited; username='%s'", self.username) self.response_param = "User administratively prohibited." return POP3_REQ_REJECT return POP3_REQ_ACCEPT Az SMTP sokkal bonyolultabb, de ha PLAIN auth történik, akkor kezelhető az alábbi proxyval import base64 class UserPolicySmtpProxy(SmtpProxy): def config(self): SmtpProxy.config(self) self.banned_users = ("alma", "korte", "test") self.request["AUTH"] = (SMTP_REQ_POLICY, self.checkUser) def checkUser(self, cmd, param): if param[:5] != "PLAIN": self.error_code = "550" self.error_info = "Only PLAIN authentication is supported." return SMTP_REQ_REJECT base64str = param[6:] try: plain = base64.b64decode(base64str) except TypeError, e: proxyLog(self, SMTP_ERROR, 3, "Unable to decode PLAIN auth request; req='%s', error='%s'", (base64str, e) ) return SMTP_REQ_REJECT try: (empty, username, password) = plain.split('\0') except ValueError,e: proxyLog(self, SMTP_ERROR, 3, "Unable to parse PLAIN auth request; req='%s', error='%s'", (plain, e) ) return SMTP_REQ_REJECT if username in self.banned_users: proxyLog(self, SMTP_POLICY, 3, "User administratively prohibited; username='%s'", username) self.error_info = "User administratively prohibited." return SMTP_REQ_REJECT return SMTP_REQ_ACCEPT Erre gondoltál? Üdv, Balint On 12/11/2013 09:51 AM, Tamas Barina wrote:

Sziasztok,

Van valamai ilyesmire lehetoseg itt:

Pop3, smtp: Ha a username != valaki1, valaki2 akkor rejectelje a kapcsolatot?

Tamas Barina

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